Optimal. Leaf size=160 \[ -\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (-a B e-A b e+2 b B d)}{e^3 (a+b x)}-\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) (B d-A e)}{e^3 (a+b x) \sqrt{d+e x}}+\frac{2 b B \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2}}{3 e^3 (a+b x)} \]
[Out]
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Rubi [A] time = 0.256505, antiderivative size = 160, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.057 \[ -\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (-a B e-A b e+2 b B d)}{e^3 (a+b x)}-\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) (B d-A e)}{e^3 (a+b x) \sqrt{d+e x}}+\frac{2 b B \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2}}{3 e^3 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(d + e*x)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 36.8681, size = 172, normalized size = 1.08 \[ - \frac{\left (2 a + 2 b x\right ) \left (A e - B d\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{e \sqrt{d + e x} \left (a e - b d\right )} + \frac{2 \sqrt{d + e x} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \left (3 A b e + B a e - 4 B b d\right )}{3 e^{2} \left (a e - b d\right )} + \frac{4 \sqrt{d + e x} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \left (3 A b e + B a e - 4 B b d\right )}{3 e^{3} \left (a + b x\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*((b*x+a)**2)**(1/2)/(e*x+d)**(3/2),x)
[Out]
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Mathematica [A] time = 0.0995576, size = 85, normalized size = 0.53 \[ \frac{2 \sqrt{(a+b x)^2} \left (3 a e (-A e+2 B d+B e x)+3 A b e (2 d+e x)+b B \left (-8 d^2-4 d e x+e^2 x^2\right )\right )}{3 e^3 (a+b x) \sqrt{d+e x}} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(d + e*x)^(3/2),x]
[Out]
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Maple [A] time = 0.008, size = 89, normalized size = 0.6 \[ -{\frac{-2\,B{x}^{2}b{e}^{2}-6\,Ab{e}^{2}x-6\,aB{e}^{2}x+8\,Bbdex+6\,A{e}^{2}a-12\,Abde-12\,aBde+16\,Bb{d}^{2}}{3\, \left ( bx+a \right ){e}^{3}}\sqrt{ \left ( bx+a \right ) ^{2}}{\frac{1}{\sqrt{ex+d}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*((b*x+a)^2)^(1/2)/(e*x+d)^(3/2),x)
[Out]
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Maxima [A] time = 0.731031, size = 101, normalized size = 0.63 \[ \frac{2 \,{\left (b e x + 2 \, b d - a e\right )} A}{\sqrt{e x + d} e^{2}} + \frac{2 \,{\left (b e^{2} x^{2} - 8 \, b d^{2} + 6 \, a d e -{\left (4 \, b d e - 3 \, a e^{2}\right )} x\right )} B}{3 \, \sqrt{e x + d} e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt((b*x + a)^2)*(B*x + A)/(e*x + d)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.30228, size = 93, normalized size = 0.58 \[ \frac{2 \,{\left (B b e^{2} x^{2} - 8 \, B b d^{2} - 3 \, A a e^{2} + 6 \,{\left (B a + A b\right )} d e -{\left (4 \, B b d e - 3 \,{\left (B a + A b\right )} e^{2}\right )} x\right )}}{3 \, \sqrt{e x + d} e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt((b*x + a)^2)*(B*x + A)/(e*x + d)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*((b*x+a)**2)**(1/2)/(e*x+d)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.286872, size = 200, normalized size = 1.25 \[ \frac{2}{3} \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} B b e^{6}{\rm sign}\left (b x + a\right ) - 6 \, \sqrt{x e + d} B b d e^{6}{\rm sign}\left (b x + a\right ) + 3 \, \sqrt{x e + d} B a e^{7}{\rm sign}\left (b x + a\right ) + 3 \, \sqrt{x e + d} A b e^{7}{\rm sign}\left (b x + a\right )\right )} e^{\left (-9\right )} - \frac{2 \,{\left (B b d^{2}{\rm sign}\left (b x + a\right ) - B a d e{\rm sign}\left (b x + a\right ) - A b d e{\rm sign}\left (b x + a\right ) + A a e^{2}{\rm sign}\left (b x + a\right )\right )} e^{\left (-3\right )}}{\sqrt{x e + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt((b*x + a)^2)*(B*x + A)/(e*x + d)^(3/2),x, algorithm="giac")
[Out]